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Post by jonklein611 on Nov 15, 2018 4:15:23 GMT -8
Got my Rapido Turbo trains in. They run great, sound great, and look great. Only issue is I can't get them to take a four digit DCC address. I've tried changing CV 29, along with 17 and 18 to change it manually. I've tried programming on the main and on a programming track. It takes a two digit just fine.
Any tips / tricks?
Jason?
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Post by bnsf971 on Nov 16, 2018 4:35:26 GMT -8
Are you programming cv 17, 18, and 29 in that order?I've tried that before, with other decoders, and if I program cv 29 first, the long address won't take.
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Post by jonklein611 on Nov 16, 2018 4:45:50 GMT -8
Are you programming cv 17, 18, and 29 in that order?I've tried that before, with other decoders, and if I program cv 29 first, the long address won't take. I'll try that tonight. Thanks for the tip.
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Post by jonklein611 on Nov 17, 2018 10:54:29 GMT -8
Tried it, didn't work. I've got a request in with Rapid to see what's going on.
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Post by jonklein611 on Dec 7, 2019 11:06:12 GMT -8
So to follow up, I wasn't thinking correctly. 4 digit address means a number greater than 128. When you're programming in 125, it's still a two digit address.
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Post by bnsf971 on Dec 8, 2019 4:03:20 GMT -8
So to follow up, I wasn't thinking correctly. 4 digit address means a number greater than 128. When you're programming in 125, it's still a two digit address. The joys of Digital, where a three digit address is really a two digit address...
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Post by ncrc5315 on Dec 28, 2019 18:37:01 GMT -8
So to follow up, I wasn't thinking correctly. 4 digit address means a number greater than 128. When you're programming in 125, it's still a two digit address. The joys of Digital, where a three digit address is really a two digit address... I wonder why that is, 128 takes two octets, so would 129, even when I run it as hexadecimal, it would still be 81. Anyone know why the dividing line is 128/129?
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Post by canrailfan on Dec 28, 2019 19:16:18 GMT -8
The joys of Digital, where a three digit address is really a two digit address... I wonder why that is, 128 takes two octets, so would 129, even when I run it as hexadecimal, it would still be 81. Anyone know why the dividing line is 128/129? NMRA DCC Standard defines a short address to be 1 to 127 (bits 0-6 or first seven bits of CV1, standard states bit 7 must be '0'). If address is set to 0 decoder will use analog mode. Dividing line is actually 127/128.
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